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![\frac{1}{3}(2x-4)+5=-\frac{2}{3}(x+1)\\\\3 \times[ \frac{1}{3}(2x-4)+5] = 3\times -\frac{2}{3}(x+1)\\\\(2x-4) + 15 = -2(x+1)\\\\2x - 4 + 15 = -2(x+1)\\\\2x + 11 = -2(x+1) \\\\2x + 11 = -2x -2\\\\4x + 11 = -2\\\\4x = -13\\\\\boxed{\bf{x = -\frac{13}{4}}}](/tpl/images/0765/0930/4b24b.png)
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