In δabc, m∠acb = 90°, cd ⊥ ab and m∠acd = 45°. find: cd, if bc = 3 in

We can find m∠BCD like follows: m∠BCD=90°-45°=45°
Now, m∠DBC= 180°-(90°+45°)=45°

Remember that , so 

We know that hypotenuse= BC= 3in and =∠DBC)=45°, so replacing the values we get:


We can conclude that the segment CD is 2.12 in

Dwould be the answer