What does the graph of y = (x + 2)(x + 1)(x – 3)2 do near the point (3, 0)? the graph is the x-axis to its left, then , and is the x-axis to its right.

I am not completely sure but I think the answer is The graph is  

below  the x-axis to its left, then  is tangent to the x-axis at the point , and is  

above  the x-axis to its right.

Step-by-step explanation:

i graphed it and analyzed it i could be wrong tho.

easy math just plug in a and b

step-by-step explanation:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: