Given the function h(x) = 3(5)x, section a is from x = 0 to x = 1 and section b is from x = 2 to x = 3. part a. find the average rate of change of each section. part b. how many times greater is the average rate of change of section b than section a? explain why one rate of change is greater than the other.

A.
h(x)=3*5ˣ; h(0)=3, h(1)=15: rate of change is (15-3)/1=12 (1st section)
h(2)=3*25=75, h(3)=3*125=375: rate of change (375-75)/1=300 (2nd section)
b.
So the second section is 300/12=25 times greater than the first section.
The function is exponential and as x gets larger the difference between consecutive values of h(x) increases dramatically so the rate of change increases.

Byou start by adding them all and setting them equal to 180 since that is half of the total degrees in a circle.(2x+8) + (3x-14) + (3x-14) = 1808x-20 = 1808x = 200x = 25

The correct answer will be d. -4