5) find an equation in standard form for the hyperbola with vertices at (0, ±6) and asymptotes at y = ±3/4 x. will mark brainliest + 10 points.

The traverse axis is vertical.the midpoint between  and is .this means the center of this hyperbola is at .the centering being at the origin means we do not have to worry about shifts.if the vertices have a distance of  from the center point, then we have  (the vertices are 6 away from the center).if the asymptotes for a vertical traverse axis hyperbola is given bythen the slope of the asymptotes are  .we are given the slopes of this particular hyperbola:   we also know that  .for positiveso if a vertical traverse axis hyperbola has the standard formthen, with  , our equation should bethe equation should be 

It’s hard to understand what you put.. can you show a picture ?