Awoman has twice as many dimes as quarters in her purse. if the dimes were quarters and the quarters were dimes, she would have $1.20 more than she now has. how many of each does she have now?

Let x = number of quarters

since she has twice as many dimes as quarters,

Let 2x = number of dimes

The total value in $ is

0.25x + (0.10)(2x)

And it was said that when the numbers of quarters and dimes are interchanged, she would have $1.20 more than the original. So,

(New Value) = (Original Value) + $1.20

0.25(2x) + 0.10x = 0.25x + (0.10)(2x) + 1.20

Solving for x,

0.5x + 0.1x = 0.25x + 0.2x + 1.20

0.6x = 0.45x + 1.20

0.6x - 0.45x = 1.20

0.15x = 1.20

x = 1.20/0.15

x = 8 quarters

2x = 16 dimes

this is a very good question

step-by-step explanation:

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b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.