When fritz drives to work his trip takes 4848 minutes, but when he takes the train it takes 4040 minutes. find the distance fritz travels to work if the train travels an average of 66 miles per hour faster than his driving. assume that the train travels the same distance as the car?

Let n be the speed of Fritzs' car, and n+6 be the speed of the train. Then:
4/5 (n)=2/3 (n+6)
4n/5=2n+12/3
10n+60=12n
2n=60
n=30
Fritz travels 4/5(30), or 24 miles to work
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The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%