Refer to scenario 4. assume that the profit equation is $110x1 + $150x2 what is the profit at corner point (0, 30)?

If you have the profit formula which is profit (x1, x2) = 110x1 + 150x2, then by substitution of the given point (x1, x2) = (0, 30), you can find the profit at the corner point profit (0.30 ) = 110 (0) + 150 (30) = 4500.Therefore the profit will be $ 4500