The length of a rectangle is 6 meters more than it's width of the the area of the rectangle is 135 square meters find it's demension

The length is 15 meters and the width is 9 meters.

If we set this up as an algebraic equation, the length, l, and the width, w, would be set up as l=w+6

Provided A=l⋅w, we can substitute l as w+6 so that A=(w+6)⋅w=w2+6w

If your Area, A is 135m2. we plug it in so that 135=w2+6w

Subtract 135 from both sides to get 0=w2+6w−135. If we factor this we get (w+15)(w−9)=0, so w=−15or9. Since distance can't be negative, w=9

If l=w+6, l=9+6=15

So the width is 9 meters and the length is 15 meters.

Hope it helps!

answ9x x 3=

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