Can somebody me? here are the two questions, in advance!

Take one step at a time. First, let's evaluate g(1):

g(1) = 2*1-3 = -1

now plug this into f: 

f(-1) = 5*-1 = -5. So the second answer is the right one.

Same approach for q 12, only now we have no value to fill in for x. What's confusing here is that the x's of f and g should not be mixed up. For the sake of clarity let's rewrite f as

f(z) = 5z + 9.

Now we'll write 3-4x everywhere we find a z. Ah, only one place.

f(g(x)) = 5(3-4x) + 9 = 15 - 20x + 9 = 24 - 20x

Idon't know the answer