Mathematics, 30.07.2019 11:50 ninilizovtskt
Verify the identity, cos 4u = cos^2(2)u - sin^2(2)u no answer choices, free response, i need !
Answers: 1
![\bf \textit{Double Angle Identities} \\ \quad \\ sin(2\theta)=2sin(\theta)cos(\theta) \\\\ \quad \\ cos(2\theta)= \begin{cases} \boxed{cos^2(\theta)-sin^2(\theta)}\\ 1-2sin^2(\theta)\\ 2cos^2(\theta)-1 \end{cases} \\ \quad \\\\ tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\ -------------------------------\\\\ cos(4u)=cos^2(2u)-sin^2(2u) \\\\\\ cos^2(2u)-sin^2(2u)\implies cos[~~2~(2u)~~]\implies cos(4u)](/tpl/images/0150/4000/38872.png)
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Verify the identity, cos 4u = cos^2(2)u - sin^2(2)u no answer choices, free response, i need !...
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