I’m a group of 55 people 33 are coffee drinkers, 12 are tea drinkers. assuming that no one in this group drinks both tea and coffee, what is the probability that a person piked random from the group does not drink tea or coffee

33+12 = 45 drink either tea or coffee (but not both)

55 - 45 = 10 people drink neither

Divide 10 over 55 and we get 10/55 = 2/11

Use a calculator to find that 2/11 = 0.1818 approximately which converts to 18.18% when you move the decimal point over 2 spots to the right



Answer as a fraction = 2/11
Answer in decimal form = 0.1818 (approximate)
Answer as a percentage = 18.18% (approximate)

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.