Every five years in march, the population of a certain town is recorded. in 1995,the town had a population of 4,500 people. from 1995 to 200, the population increased by 15%. from 2000 to 2005,the population decrease d by 4%. what was the town's population in 2005?

From 2000 to 2005,the population decrease d by 4%. What was the town's population in 2005?
The first thing we want to look at is that from 1995 to 2000, the population increased by 15% (from 4,500.) So that means we multiply 4,500 times 15% to get 15% of 4,500.
.15*4,500=675 (.15 is the same thing as 15%)
So we see it increased by 675.
4,500+675=5175
So in 2000, there were 5,175 people
So now we do the same thing for 2000 to 2005. 
The population has decreased by 4% (or .04)
Now to see what 4% of 5,175 is we multiply is by 4% 
.04*5175=207
So now if it has decreased by 207 (4% of the population in 2000)
Now we subtract that number from the population in 2000
5175-207=4968
In 2005 there are 4968 people.

Answer: 10pi

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

For range i think it’s area