Shota is a dangerous fellow who likes to go rock climbing in active volcanoes. one time, when he was 30 meters below the edge of a volcano, he heard some rumbling, so he decided to climb up out of there as quickly as he could. he climbed up at a constant rate. after 4.5 seconds, he was 7.5 meters below the edge of the volcano. how fast did shota climb? in total how long did it take shota to reach the edge of the valcano?

His rate of climbing = 5 meter /second and total time to reach the edge of volcano  = 6 second

Step-by-step explanation:

Here, According to the question,

The total distance he would cover= 30 meter.

The distance covered by him in 4.5 second = 30 - 7.5= 22.5 meter.

Thus, his speed = = 5 m/s ( because speed = distance/ time)

Since, the remaining distance he has to cover= 7.5 meter

So, the time taken by him to cover the distance=  7.5/5= 1.5 seconds

Therefore the total time taken to cover the distance of 30 meter,

T= 4.5 + 1.5 = 6 second.

yeet

step-by-step explanation:

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!