The perimeter of a triangle is 39 inches. the second side is 9 times as long as the first side. the third side is 1 inch longer than the second side. find
the length of each side.

Perimiter=x+y+z
x is 9 times as long as y
z is 1 longer than x

translate
x=9 times y or x=9y
z=1+x
subsitute 9y for x in the z=1+x equation
z=1+9y
subsitute z=1+9y and x=9y in the equation
9y+y+1+9y=39
add like terms
19y+1=39
subtract 1 from both sides
19y=38
divide by 19
y=2
subsitute
x=9y
x=9(2)
x=18

z=1+9y
z=1+9(2)
z=1+18
z=19

the side legnths are
first side: 2 in
second side: 18 in
third side: 19 in

Ithink if im not mistaking b is -3 but im not a 100% sude