If triangles abc and xyz are in perspective, name or describe the points that must be collinear according to the desargues’ theorem. a. ab and xz, ac and xy, bc and yz c. ab and bc, ac and xz, bc and yz b. ab and xy, ac and xz, bc and yz d. ab and xy, ac and xy, bc and yz  

b. AB and XY, AC and XZ, BC and YZ.

Step-by-step explanation:

Given

two triangles ABC and XYZ

Corresponding side of AB is XY.

Corresponding side of BC is YZ.

Corresponding side of AC is XZ.

Desargues theorem: If two triangles ABC and A'B'C' in a plane .

The line AA', BB' and CC' intersect at a single point if and only if the intersection of corresponding sides (AB.A'B') ,(BC,B'C') and ( AC, A'C')  lie on a single line.

Therefore, in given triangles ABC and XYZ  the line AX, BY, CZ intersect at a single point .

Then the intersection of corresponding sides (AB,XY), (BC,YZ) and ( AC, XZ) lie on a single line.

By Desargues theorem w

we can say Side AB and XY, AC and XZ, BC and YZ are collinear.

Hence, option b is correct.

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

c-   36

taxicab circle radius 9 has 4(9) = 36 points