Over what interval is the function in this graph increasing ?

-4 ≤ x ≤ 1

Step-by-step explanation:

-4 ≤ x ≤ 1

Step-by-step explanation:

A function f(x) is called increasing in an interval [a,b] when f'(x) > 0 in the interval (a,b).

That is, in that interval, with increasing the value of x the value of f(x) increases.

Let f(x) be the function which is shown in the given diagram.

Since, by the given diagram,

In the interval , f(x) decreases as x increases,

Hence In this interval given function is decreasing.

In the interval [-4, 1], f(x) increases as x increases,

Hence In this interval given function is increasing.

In the interval (1,6), f(x) is constant as x increases,

Hence In this interval given function is neither increasing nor decreasing.

In the interval , f(x) decreases as x increases,

Hence In this interval given function is decreasing.

answer:

(-8,7)

explanation:

we know that  

f

(

−

3

)

=

7

therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.

looking at the function  

f

(

x

+

5

)

, what should the value of x be, such that the input in the function becomes 7?

we simply equate the terms,

x

+

5

=

−

3

x

=

−

8

thus, the point on the new function would be  

(

−

8

,

7

)

ok

step-by-step explanation: