Aspinner is divided into four equal sections that are numbered 1, 3, 4, and 6. the spinner is spun twice. how many outcomes have a sum greater than 5 and contain at least one odd number?

7. Since each spin can be considered an independent event and that there's only 4 possible outcomes for each event, we can trivially, enumerate all 16 possible combinations and examine them to see if they meet the desired criteria. So: 11, 13, 14, 16, 31, 33, 34, 36, 41, 43, 44, 46, 61, 63, 64, 66 Let's prune the above list to just those with a sum greater than 5. 16, 33, 34, 36, 43, 44, 46, 61, 63, 64, 66 Now prune the above list to just those with an odd number. 16, 33, 34, 36, 43, 61, 63 And finally, count them to determine that there's 7 possible outcomes.

Y=3x+1 so the first one

The answer is 76° i believe