Answers: 1
![\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad \sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}} \\\\\\ \left.\qquad \qquad \right.\textit{negative exponents}\\\\ a^{-{ n}} \implies \cfrac{1}{a^{ n}} \qquad \qquad \cfrac{1}{a^{ n}}\implies a^{-{ n}} \qquad \qquad a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\ -------------------------------](/tpl/images/0142/7320/7b3c4.png)
![\bf \left( g^{\frac{2}{3}} \right)^2\cdot g^{-2}\implies \left( g^{\frac{2}{3}} \right)^2\cdot g^{-2}\implies \left( g^{\frac{2}{3}\cdot 2} \right)\cdot g^{-2}\implies g^{\frac{4}{3}}\cdot g^{-2} \\\\\\ g^{\frac{4}{3}-2}\implies g^{\frac{4-6}{3}}\implies g^{\frac{-2}{3}}\implies \cfrac{1}{g^{\frac{2}{3}}}\implies \cfrac{1}{\sqrt[3]{g^2}}](/tpl/images/0142/7320/4b63f.png)
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You know the right answer?
Provide an explanation as well! (g^2/3)^2 *g^-2...
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