How do i evaluate lim (tan2x)^x x-> 0+ i think you have to do l’hospitals but we have to prove at every step

Hmm.. if we plug zero in for x like any other limit, anything to the power of 0 is 1, so as x approaches 0 from above the limit would be 1.

L’Hospital’s rule only applies if the limit is 0/0 or ∞/∞. But we don’t have a fraction. Unless there is another stupid trig identity of tan that I’m forgetting lol.

I’m not sure how you’d prove every step with this one, but I hope this helped a little

If jon had $4.00 then takes away $2.25, then he should have $1.75 left. $4.00 - $2.25 = $1.75 hope this ; )