Scores on a standardized test are normally distributed with a mean of 350 and a standard deviation of 25. approximately what percent of students scored between 360 and 380?

22.95 %

Step-by-step explanation:

Given : Scores on a standardized test are normally distributed with

Mean :

Standard deviation :

The formula to find z-score:-

For x=360

For x=380

The p-value =

In percent , the percent of students scored between 360 and 380 =

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!