Mathematics, 27.07.2019 10:30 gwen8605
Use lagrange multipliers to find the point on the plane x β 2y + 3z = 6 that is closest to the point (0, 2, 5).
Answers: 1
.
=
k(1,-2,3)
, but it's easy to see that 
and 
have critical points at the same vector 
.
, we get a single critical point at 
, which in turn gives the least distance between the plane and (0, 2, 5) of 
.
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Use lagrange multipliers to find the point on the plane x β 2y + 3z = 6 that is closest to the point...
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