In a dog show, there will be a gold, a silver, and a bronze medal awarded. there are 5 finalists. in how many different ways can the 3 medals be awarded?

The number of different ways can the 3 medals be awarded=20.

Step-by-step explanation:

Given: In a dog show, there will be a gold, a silver, and a bronze medal awarded. there are 5 finalists.

By using permutation,

Number of different ways can the 3 medals be awarded=

Therefore, the number of different ways can the 3 medals be awarded=20.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.