Identify the triangle that contains an acute angle for which the sine and cosine ratios are equal.

we have to consider a triangle whose acute angle measure is 45° so that the sine and cosine ratios are equal.

Step-by-step explanation:

We need to consider a right angled triangle such that the measure of one of angle is 90° ,the second angle is 45° and hence the third angle could be found by using the fact that the sum of all the angles is 180°.

Hence we get the third angle measure to be 45°

( ∠1+∠2+∠3=180°

90+45+∠3=180

∠3=180-(90+45)

∠3=45° )

so in the right angled triangle if we use our trignometric identity along either angle 2 or angle 3 we get;

sin 45°=

and cos 45°=  

Hence the sine and cosine angle are equal.

So we have to consider a triangle whose acute angle measure is 45° so that the sine and cosine ratios are equal.

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.

false

step-by-step explanation:

false : it can not go to 9 the highest that part can go is 7

here is your proof