1.) which relation is a function? a {(–3, 4), (–2, 5), (0, 9), (0, 12)} b. {(8, –1), (2, –1), (3, 8), (2, 5} c. {(7, 12), (1, –5), (3, –10), (2, –5)} d. {(1, 2), (1, 5), (1, –1), (1, 4)} 2.)which relation is a function?

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

22 dimes and 9 nickels

step-by-step explanation: