Mario and patience are making cookies. they are ready to drop balls of dough on baking sheets. they have baking sheets made of treated glass, aluminum, stainless steel, and copper. the specific heats of these substances are: treated glass = 0.75 j/g • °c aluminum = 0.90 j/g • °c stainless steel = 0.50 j/g • °c copper = 0.39 j/g • °c based on the specific heat values, which sheet is going to warm up the quickest, and, therefore, bake the cookies the fastest?

Specific heat of different materials is different. The copper sheet is going to warm up the quickest, and, therefore, bake the cookies the fastest.

Specific heat is the amount of heat needed to raise the 1° C temperature of a unit mass of material. It is given by the formula,

Where Q is the amount of heat, m is the mass, T is the difference in the temperature.

As we have discussed that specific heat is the tells as the amount of heat that is been needed, therefore, if the specific heat of a material is less that means the material will take less time to heat.

Treated glass = 0.75 J/g • °C

Aluminum = 0.90 J/g • °C

Stainless steel = 0.50 J/g • °C

Copper = 0.39 J/g • °C

If we compare all the materials, the material with the least specific heat is copper, therefore, the copper sheet is going to warm up the quickest, and, therefore, bake the cookies the fastest.

Learn more about Specific Heat:

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Copper

Step-by-step explanation:

Heat = specific heat•mass•temperature change

Assuming that all sheets have the same mass and the oven transfers the same amount of heat to them, then the quantity: heat divided by mass is constant in all 4 cases.

Heat/mass = specific heat•temperature change = constant

As specific heats increase, temperature change of the material decrease, so that, their multiplication remains constant. Then, the material with the lowest specific heat will have the greatest temperature change, i. e., warms up quickest. Cooper is that material.

x^5/3y^1/3 the correct answer

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step-by-step explanation: