Acircle has a radius of 9 cm and a sector of the circle has an arc length of 9.7 cm.

the angle at the centre of the sector is x°.

calculate the value of x to the nearest degree.

The value of X is 62 degrees

Step-by-step explanation:

The arc length L  of a circle is given by formula:

L= 2(pi)(r)X / 360 (1)

where pi = 3.14, r is the radius of the circle and X the angle that produces the arc. You want the angle X so we can simplify X in equation (1)

360L=2(pi)(r)X

360L/2(pi)(r)= X

X =  360L/2(pi)(r)

We replace the radius r=9cm the arc L = 9.7 cm and pi and obtain

X = 360* (9.7 cm)/ 2(3.14)*(9cm) = 3492/56.52 = 61.78

That rounded to nearest degree is 62 degrees.

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0