Asock drawer has 8 blue socks and 6 black socks. if i randomly select two socks, one at a time, what is the probability i will first get a blue sock and then, without replacing it, a black sock? a. 24/91 b. 2/7 c. 6/81 d. 4/13

Calculate first the total number of permutation possible.

You select two socks so that will be:

14⋅13=182

Now you must first select a blue sock then a black sock:

You can only pick 8 possible blue socks
You can only pick 6 possible black socks

which means that this permutation (blue→black) have 8⋅6=48 possibilities for each different blue and black sock.

express in fraction:

48182=2491

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

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step-by-step explanation: