Given: ∆dek, de = ek

ef −∠ bisector of ∠e
m∠def = 44°, dk = 16
find: kf, m∠dek,
m∠dfe

KF=8, m<DEK=88degrees, m<DFE=90 degrees

Step-by-step explanation:

Since we already know that DK is 16 you would just have to /2 to get KF=8

m<DEK=88degrees because we already know half of the angle because EF is a bisector. so 44*2=88

m<DFE=90degrees because since EF is a bisector it split it right down the middle meaning it would be equal to 90degrees.

Hope this helps! :)

answer: it is 1: 47 pm

the answer is 45 i just did it on oddesy ware