Xvaries jointly with the square of y and z. when y=6 and z=5, x=100. then, what is x when y=8 and z=2?

X = k*y^2 * z
100 = 6^2*5*k,
k=0.555
x=0.555zy^2

x=o.555(8^2)(2)=71.1112.

Hope that helps!

Answer: the correct answer is 10step-by-step explanation: let the number be n, then the expression becomes,then“twelve more than the quotient of a number and two, decreased by four” iswhen n=4,we substitute 4 whetever we see n to get,we simplify to obtain,we further simplify to get,therefore the correct answer is c.

I’m confused this is what i’m doing in class but the question is confusing