Find tthe solutions of x^2-6x+2=0 explain your answer.

The answer is C., and you figure this out through completing the square

First bring 2 to the other side of the equation making it x^2 -6x =2

Then find a new c term by doing (b/2)^2

This is (-6/2)^2 which is (-3)^2, = 9

Now you have x^2 -6x + 9 =-2. However since you added 9 to one side of the equation, you must add 9 to the other side in order to balance it out

So it is x^2 -6x+9 = -2+9

Factor the first side of the equation and add the second side to simplify:

(x-3)^2 = 7

Take the square root of both sides and you get x-3 is equal to the square root of plus/minus 7

Then add three to both sides to isolate x and you get your final result which is x= 3 plus/minus radical 7

Well in order to lose a pound you would have to burn 1,500 calories. the more calories you burn the more weight you lose. in order to lose 2 pounds you would have to run 4 hours and 28 minutes.

2.4+3.2t. you get the answer by adding the ones with variables and ones without