Heeel aaasspp verify (a-5)(a+5)=a^2-25 (x-88)(x+88)=x^2-88^2 a^2-b^2=(a-b)(b-a) solve for x x^2-9=5(x-3) (w+2)(w-5)=w^2-4 solve x^2-11x=0 for x the square of a number plus 3 times the number is equal to four . what is the number. is b factorable x^2+bx+12 x^2-3x+b

Okay so first off I do not know if any of these are completely correct, as well as I totally forgot how to solve the last two. Either way, this is what I got for them. 
The first is true
The second would be true although -88 squared is 7744 and the equation equals -7744 which can not be obtained by a square number of negative times a negative is a positive number. The third is not true for you do have -a^2 and -b^2 but you also end up with aB as well as -bA. The fourth in decimal form would be.167 The fifth again in decimal form would be 1.732 Then the next would be 0. Finally, the next one would be .090 Again, I do not know how to solve the last two and I honestly do not know if anyone of these is correct. 

Answer:

$4034.40

step-by-step explanation:

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40