The solution to the following system of linear equations lies in which quadrant? −2x + 3y = 8 4x + y = −2

First, let's find the solution.

-2x + 3y = 8
Add 2x to both sides.
3y = 2x + 8
Divide both sides by 3.
y = 2/3x + 8/3

4x + 2/3x + 8/3 = -2
14/3x + 8/3 = -2
Subtract 8/3 from both sides.
14/3x = -14/3
Multiply both sides by 3/14.
x = -1

y = 2/3(-1) + 8/3
y = -2/3 + 8/3
y = 6/3, or 2.

The solution is (-1, 2) which lies in Quadrant II, because its outline is (-, +).