Acaravan crossed 1,378 miles of desert in 85 days. it traveled 22 miles on the first day and 28 miles on the second day. if the caravan traveled the same number of miles on each of the remaining days, how many miles did it travel on each of those day?

The caravan traveled 16 miles each day

Step-by-step explanation:

The caravan covers a distance of 1378 miles in 85 days. The first day he covered a distance of 22 miles and the second day it covered a distance of 28 miles. The remaining days will be 85 days minus the 2 days we already know the distance the caravan covered which is 83 days.

According to the question the remaining days he covered has equal distance for each day.

let y = miles covered each day in the remaining 83 days  

So total distance covered in those 83 days is 83 × y

Total distance covered for 85 days = 1378 miles

first day  = 22 miles

second day = 28 miles

Remaining 83 days = 83 × y

1378 = 22 + 28 + 83 × y

1378 - 22- 28 = 83y

1328 = 83y

y = 1328/83

y = 16

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3