1. find all solutions for the equation 4x3 12x2 – 40x = 0. show and explain your work

To answer this question, we have to do the following:
Because I don't know if there is a + between 4x3 and 12x2 or a -, I will calculate it for both:

4x^3 + 12x^2 -40x = 0
4x*(x^2 + 3x - 10) = 0 
4x*(x+5)*(x-2) = 0 

1. x = 0 (the answer for the first x in the equation)
2. x = - 5 (the answer for the second x in the equation)
3. x = 2 (the answer for the third x in the equation)

OR

4x^3 - 12x^2 - 40x = 0
4x*(x^2 - 3x - 10) = 0
4x*(x - 5)*(x + 2) = 10

1. x = 0
2. x = 5
3. x = -2