All movies until 4: 00 pm require a discount ticket, and all movies after 4: 00 pm required a regular price ticket. each theater at the movie plex seats 98 people. what is the least number of showings the theater could have shown after 4: 00 pm last saturday? explain how you found your answer.

13 showings.

Step-by-step explanation:

Using the information about the question given in the comments, we know that there are 1456 tickets sold the weekend in question.  We also know that they sold 6 times as many regular price tickets as they did discount tickets.

Let r represent regular price tickets and d represent discount tickets.  Since there were 6 times more regular price than discount, we get

r = 6d

Together, there were 1456 tickets sold:

r + d = 1456

Substitute our value from the first equation into the second:

6d + d = 1456

Combine like terms:

7d = 1456

Divide both sides by 7:

7d/7 = 1456/7

d = 208

There were 208 discount tickets sold.  This means there were 6(208) = 1248 regular price tickets sold.

The regular price tickets are sold after 4:00.  There are 98 seats in each showing; this means they needed

1248/98 = 12.7 ≈ 13 showings.

the solution is h=10 because you add 9 to each side of the equation.

answer: idk

step-by-step explanation: