The current size of an image on sandy's computer is shown below: what are the dimensions of the image at fraction 1 over 2 times its current size? a. length = 8 inches, width = 12 inches b. length = 6 inches, width = 8 inches c. length = 2 inches, width = 4 inches d. length = 2 inches, width = 3 inches

Hello!

From our given picture, we have the dimensions 4 and 6; the length and width.
Let's take a look at our question. "What are the dimensions of the image at fraction  times its current size?"
This question is asking for what would be the dimensions if we set our scale factor as 2:1 (Original to New), so let's divide our dimensions by 2 (or multiply by 0.5 - either works).

6 / 2 = 3 (Width)
4 / 2 = 2 (Length)

Our new dimensions are 3 for the width and 2 for the length.

Answer choice "D. Length = 2 inches, width = 3 inches" fits our concluded answer; therefore, the answer choice is "D.)"

I hope this helps!

Sin(a)+cos(a)+cot(a)-1=2(csc(x)+1)