Earth has a radius of 6371 kilometers. a pilot is flying at a steady altitude of 5.6 kilometers above the earth's surface. what is the pilot's distance to the horizon? enter your answer, rounded to the nearest tenth, in the box.

The pilot's distance to the horizon is 267.2 kilometers.

Step-by-step explanation:

According to the below diagram,   is the position of the pilot which is 5.6 kilometers above the earth's surface, .

Earth has a radius of 6371 kilometers. That means, kilometers.

So,   kilometers.

The pilot's distance to the horizon is .

Using Pythagorean theorem, we will get........

(Rounded to the nearest tenth)

So, the pilot's distance to the horizon is 267.2 kilometers.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.