Me solve each system by elimination? 1) -4x-8y=16 8x+16y=-16 2) 4x-10y=-14 3x+8y=-26 you!

1)
-4x-8y=16
8x+16y=-16

Multiply fhe first equation by 2:

=> -8x - 16y = 32

Add this new equation with previous second equation

0 = 16, which means that the system has no solutions.

2)

4x-10y=-14
3x+8y=-26

Multiply the first equation by 3 and the second by - 4:

 12x - 30y =   - 42
-12x - 32y =   104

Add the two new equations

0 - 62y = 62

=> y = -1

replacing in the first equation:

=> 4x-10(-1) = -14

=> 4x + 10 = - 14

=> 4x = - 14 - 10

=> 4x = - 24

=> x = - 24 / 4

=> x = - 6

x = - 6 and y = - 1

Hello! mark me brainliest
answer:
congruent segments
step-by-step explanation:
congruent segments. take a line, cut it in half, superipose one half over the other half; you'll have congruence.