Triangle rst has vertices r(2, 0), s(4, 0), and t(–3, –1). the image of triangle rst after a rotation has vertices r'(0, –2), s'(0, –4), and t'(–3, –1). which rule describes the transformation? r0, 90° r0, 180° r0, 270° r0, 360°

It should be C aka 270°

Step-by-step explanation:

3 option is correct.

Step-by-step explanation:

Given Triangle RST has vertices R(2, 0), S(4, 0), and T(–3, –1). The image of triangle RST after a rotation has vertices  R'(0, –2), S'(0, –4), and T'(–3, –1).

We have to tell the rule describes the transformation.

A rotation is transformation that turns a figure about a fixed point. An object and its rotation are the same shape, but the figures may turned or rotate in different directions.

Here, the coordinates shift after rotation according to the rule

(2,0) → (0,-2) i.e (x, y) → (y, -x)

As, Rotation of 270º on coordinate axes.

(x, y) → (y, -x)

which match to the given rule.

hence, 3 option is correct.

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0