Abaker sells bread for $5 a loaf and rolls for $1 each. the baker needs to sell $35 worth of baked goods by the end of the day. enter a linear equation that describes the problem.

To be able to express the given scenario through the equation, we are to represent the number of loaves by the variable x and y for the number of baked goods. 

Given the costs and the variables, the linear equation is,
 
                      5x + y = 35

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.