What are the domain restrictions of q^2−7q−8 divided by q^2+3q−4 ? q≠1 and q≠−8 q≠−1 and q≠8 q≠−1 and q≠4 q≠1 and q≠−4

Factorize the polynomials individually; 

q²-7q-8= (q-8)(q+1) <-- denominator 
q²+3q-4= (q-1)(q+4) 

When a number is divided by 0, it becomes indefinite (creating a hole in the graph). 

(q-8)(q+1)=0 
q=8
q=-1

Therefore, the second option.

Hope I helped :) 

Lol idk ask google. ejie