Find the coordinates of point p p along the directed line segment ab ab , from a(1, 6) a(1, 6) to b(−2,−3) b(−2,−3) , so that the ratio of ap ap to pb pb is 5 5 to 1 1 .

Here is the formula for finding a partitioning point:
x=x1+k(x2-x1), y=y1+k(y2-y1)
k is the ratio of the segment from the beginning point to the partitioning : the whole segment. In this case, k=AP:AB=5/16
so x=1+(5/16)*(-2-1)=1/16
y=6+(5/16)(-3-6)=51/16
so the answer is (-1/16, 51/16)

Please double check my calculation by yourself.

refer to this website for the formula and how to find k:

"This ratio is called k, and is determined by writing the numerator over the sum of the numerator and the denominator of the original ratio."
https://cobbk12.blackboard.com/bbcswebdav/institution/eHigh%20School/Courses/CCVA%20CCGPS%20Coordina

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

the value of x is equal to 0.