Let f(x)=2(3)^x+1 +4. the graph of f(x) is stretched vertically by a factor of 2 to form the graph of g(x). what is the equation of g(x)?

G(x) = (3)^(x+1)  + 4

hope it helps

Note:  It's important that you enclose that exponent, x+1, inside parentheses:

f(x)=2(3)^(x+1) +4.

g(x) = 2[2(3)^(x+1)] + 4 (do not mult. that 4 by 2).
           
        = 4*3^(x+1) + 4 (answer)

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