Acompany produces steel rods. the lengths of the steel rods are normally distributed with a mean of 108.7-cm and a standard deviation of 0.6-cm. for shipment, 22 steel rods are bundled together. find the probability that the average length of rods in a randomly selected bundle of steel rods is less than 109.1-cm. round to 4 decimal places. answers obtained using exact z-scores or z-scores rounded to 2 decimal places are accepted.

Let x be the lengths of the steel rods and X ~ N (108.7, 0.6)

To get the probability of less than 109.1 cm, the solution is computed by:

z (109.1) = (X-mean)/standard dev

= 109.1 – 108/ 0.6

= 1.1/0.6

=1.83333, look this up in the z table.

P(x < 109.1) = P(z < 1.8333) = 0.97 or 97%

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!

step-by-step :