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![\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad \sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\ -------------------------------\\\\ \sqrt[4n]{3^2}\implies 3^{\frac{2}{4n}}\implies 3^{\frac{1}{n}}](/tpl/images/0116/5284/eb047.png)
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