How do you solve 2x²-x=3 by factoring

the value of x are -1 and  

Step-by-step explanation:

we need to find the factor of 2x²-x=3  

subtract both the sides by 3, in above expression

2x²- x - 3 = 3 - 3

2x²- x - 3 = 0

we can write  x as -3x + 2x

2x²- 3x +2x - 3 = 0

2x²+ 2x -3x - 3 = 0

take out the common terms,

2x(x+ 1) -3(x +1) = 0

(x+ 1)(2x-3) = 0

If x+ 1 =0

⇒ x = -1

If 2x - 3=0

⇒

Therefore, the value of x are -1 and  

18.36. give me brainliest!

step-by-step explanation:

you have to multiply 1.53 by 12 so the equation is 12x1.53 and then that is your answer.

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12