Use the functions h(x) = 2x + 5 and t(x) = 7x − 6 to complete the function operations listed below. part a: find (h + t)(x). show your work. (3 points) part b: find (h ⋅ t)(x). show your work. (3 points) part c: find h[t(x)]. show your work. (4 points)

 h(x) = 2x + 5 and t(x) = 7x − 6

Part A: Find (h + t)(x)
(h + t)(x) = 2x + 5  + 7x − 6
(h + t)(x) = 9x  − 1

Part B: Find (h ⋅ t)(x).
(h ⋅ t)(x) = (2x + 5 ) ( 7x − 6)
(h ⋅ t)(x) = 14x^2  + 35x - 12x - 30
(h ⋅ t)(x) = 14x^2  + 23x  - 30

Part C: Find h[t(x)].
h[t(x)] = 2(7x − 6) + 5 
h[t(x)] = 14x  − 12 + 5 
h[t(x)] = 14x  − 7

Option ait states the correct answer

You need to divide 210 square inches by 35 inches and that’s going to give you 6 inches and that’s the length of the hypothenuse of the right triangle i hope that this you : )