Mathematics, 20.07.2019 22:00 rodriguezzamyy
Evaluate the surface integral s is the triangular region with vertices (1, 0, 0), (0, 5, 0), (0, 0, 5)
Answers: 1
, in which case we can parameterize the surface by
. Then the area of ![\displaystyle\iint_{\mathcal S}\mathrm dS=\int_{[0,1]^2}\|\mathbf s_u\times\mathbf s_v\|\,\mathrm dv\,\mathrm du](/tpl/images/0113/1906/384f9.png)
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Evaluate the surface integral s is the triangular region with vertices (1, 0, 0), (0, 5, 0), (0, 0,...
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