Use the standard normal table to find the z-score that corresponds to the given percentile. if the area is not in the table, use the entry closest to the area. if the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. if convenient, use technology to find the z-score. upper p 8p8

You need to look for the area to the left of the z-score from the table. 
i found a z-score of.84 yielded .7995 area to the left of that z-score and i found a z-score of .85 yielded .8024 area to the left of that z-score. 
0.7995 is much closer to 0.80 than 0.8024, so the z-score chosen as the solution is a z-score of .84. 
the z-score of .84 is an addition of 0.8 in column 1 with .04 in column 7 
 
it's the intersection of the area in the row of .8 with the column of .04. 
this is shown in the following picture.

Using the standard normal table, it is found that the z-score corresponding to the upper p8 is z = 1.405.

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In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:

It measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the standard normal table and find the p-value associated with this z-score, which is the percentile of X. The upper p8 is the 100 - 8 = 92th percentile, which is Z with a p-value of 0.92.Looking at the standard normal table, we get that this value is of z = 1.405.

A similar problem is given at link

The answer is a hope i